How to pass arguments to an alias in bash

Lets look at passing arguments to an alias by looking at an example.

The below command will open duckduckgo.com in a new tab in firefox.

firefox --new-window duckduckgo.com

Lets say, I want to create an alias but I want to pass the URL as a parameter to the alias.

For example, if I run the following command in the terminal, it should look at the first argument (which is the URL) and open it in a newtab in firefox.

ff duckduckgo.com

To achieve this, you can do the following:

Edit your ~/.bashrc or ~/.bash_profile using your favorite editor.

vim ~/.bashrc

Create a function inside the ~/.bashrc  with the following content. [Copy/paste the below inside your bashrc]

alias ff='function _ff()
{
firefox --new-window $1
};_ff'

Here, $1 is the first argument.

Once you save and close the bashrc file, you can source your bashrc for changes to take affect.

source ~/.bashrc

Now, if you enter the following command in the terminal, it will take “duckduckgo.com” which is the 1st parameter and open it in a new tab in firefox.

ff duckduckgo.com

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Source: StackOverFlow